Question

cube root of 3 by 5 whole to the power 2x + 1 = 125 by 27
​

Answer 1

$x= -5$

Step-by-step explanation:

Given equation

$(\sqrt[3]{3/5})^{2x+1}=125/27$

then simplify the equation

$\left ( 3/5 \right )^{(2x+1)/3}=\left ( 5/3 \right )^{3}$

convert same base form               $\left ( a/b \right )^{m}=\left ( b/a \right )^{-m}$

$\left ( 3/5 \right )^{(2x+1)/3}=\left ( 3/5 \right )^{-3}$

if base is same then compare the power and find out the value of x

$\left ( 2x+1 \right )/3=-3$

$2x+1=-9$

$2x=-10$

$x=-5$