Current is 40mA time is one minute then what will be the no of electrons?
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I = 40 mA
t = 60s
charge, q = It = 40 × 60 = 2400 mC = 2.4 C
charge in 1 electron = 1.6 × 10^(-19) C
total electrons in 2.4 C = 2.4 ÷ (1.6 × 10^(-19)) = (2.4/1.6) × 10^(19) = 1.5 × 10^(19) electrons
t = 60s
charge, q = It = 40 × 60 = 2400 mC = 2.4 C
charge in 1 electron = 1.6 × 10^(-19) C
total electrons in 2.4 C = 2.4 ÷ (1.6 × 10^(-19)) = (2.4/1.6) × 10^(19) = 1.5 × 10^(19) electrons
Answered by
0
I = 40 mA
t = 60s
charge, q = It = 40 × 60 = 2400 mC = 2.4 C
charge in 1 electron = 1.6 × 10^(-19) C
total electrons in 2.4 C = 2.4 ÷ (1.6 × 10^(-19)) = (2.4/1.6) × 10^(19) = 1.5 × 10^(19) electrons.
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