Question

Cyclist starts from rest and acceleration at the rate of 2 metre per second square what will be his velocity after 5 seconds.

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Answer with explanation~​

Answer 1

Gɪᴠᴇɴ : - u = 9; a = 1 m/sec^2; t =20 sec.

ᴅɪᴅ ᴜ ᴋɴᴏᴡ ᴛʜᴀᴛ :-

v=u+at; v=0+1*20 = 20

First distance:

s=1*20^2/2 = 200 m.

Second distance:

20*60 = 1200 m.

Third distance:

0 = 20-2*t; t = 10 sec

s = 20*10–2*100/2=100 m.

Total distance=200+1200+100 = 1500 m.

Maximum velocity is v = 20 m/sec or 20*18/5 = 72 km/hour.

Answer 2

$\huge \fbox \pink{Given}$

$\sf Initial \: velocity \: (u) = 0 \:$

$\sf \: Acceleration \: (a) = 2 \:$

$\sf \: Time \: taken(t) = 5 \:$

$\huge \fbox \blue{To \: find}$

$\sf \: Velocity \: of \: cyclist \:$

$\huge \fbox\red {Answer}$

Here, we will apply newton first Equation.

Putting values

$\sf \: v \: = 0 + 2 (5)$

$\sf \: v \: = 0 + 2 \times 5v$

$\sf \: v \: = 0 + 10$

$\sf \: v \: = 10 \:$

$\bf \therefore \: Velocity \: of \: cyclist \: = 10 \:$