Question

Cyclist starts from rest and acceleration at the rate of 2 metre per second square what will be his velocity after 5 seconds.

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Answer with explanation~
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Answer 1

$\huge \fbox \pink{Given}$

$\sf Initial \: velocity \: (u) = 0 \:$

$\sf \: Acceleration \: (a) = 2 \:$

$\sf \: Time \: taken(t) = 5 \:$

$\huge \fbox \blue{To \: find}$

$\sf \: Velocity \: of \: cyclist \:$

$\huge \fbox\red {Answer}$

Here, we will apply newton first Equation.

Putting values

$\sf \: v \: = 0 + 2 (5)$

$\sf \: v \: = 0 + 2 \times 5v$

$\sf \: v \: = 0 + 10$

$\sf \: v \: = 10 \:$

$\bf \therefore \: Velocity \: of \: cyclist \: = 10 \:$

Answer 2

Refer to attachment.....