Question

D={2,9,28,65} write it in set builder form​

Answer 1

Answer:

Step-by-step explanation:

The series 2,9,28,65,_,217 is (N^3+1) where N starts from 1.

(1^3)+1 = 1+1 =2

(2^3)+1 = 8+1 =9

(3^3)+1 = 27+1 =28

(4^3)+1 = 64+1 =65

Answer 2

Given : D={2,9,28,65}

To Find : write it in set builder form​

Solution:

2 = 1³ + 1

9 = 2³ + 1

28 = 3³ + 1

65 = 4³ + 1

x³  + 1    ,  1 ≤ x ≤ 4

Set builder form

{ x³  + 1 :  x ∈ N ,  1 ≤ x ≤ 4}

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