D bcm C
M
N
35. In a trapezium ABCD, AB|| DC, AB = a cm, and
DC = b cm. If M and N are the midpoints of the
nonparallel sides, AD and BC respectively then
find the ratio of ar(DCNM) and ar(MNBA).
B
A
a cm
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Join The diagonal DB Which Cuts the line MN at the point Y.
[look at the pic]
we know that M and N are the midpoints of AD and BC
- We know that M is the midpoints of AD and MY||AB
- So we get Y as the midpoint of BD it can be written as
we know that
We Get
- it is given that AB=a and CD=b so we get
- Construct DQ⊥AB where DQ cuts the line MN at the pòinť P.
So we know that P is the midpoint of DQ it can be written as
we get
so we get
So we get
it can be written as
Area of Trapezium DCNM:Area of Trapezium MNBA
Therefore Ratio of area (DCNM) And area (MNBA) is
━━━━━━━━━━━━━━━━━━━━━━━
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