Question

d/dx [log(log x)]
solve this differentiation question.
​

Answer 1

Answer:

d/dx[log(logx)] = 1/logx * 1/x = 1/x(logx)

Explanation:

Using chain rule, we should first find the differential of the main function log(logx) [which is 1/logx]  and then multiply it with the differential of the subsequent function contained inside the main function, which is logx in this case. [i.e, diff. of logx = x]

So 1/logx * 1/x =1/x(logx)