Question

using reminder theorem find he value of k so that(4x^2+kx-1) leaves the reminder 3,when devided by x-4

Answer 1

Answer: your answer is k = -15.

Step-by-step explanation:

4x²+kx-1 = 3

4×4²+k×4-1 =3

4×16+4k-1=3

64+4k-1=3

63+4k=3

4k= -63+3

4k= -60

Therefore k =-15

Hope it helps if it helps please give thanks

Answer 2

• If the question is (4X/2+Kx-1)

Step-by-step explanation:

Answer:

p(X)=0

X-4=0

hence,X=4

Putting value of X in equation,then

4*4/2+4*K-1=3

=8+4K-1=3

=4K=3+1-8

=4K=-4

=K=-1

hence answer is -1.So this is the value of K.