D is a point on the side BC of a triangle ABC, A line PDQ, through D, meets side AC in P and AB produced at Q. If angle A =80° , angle ABC = 60° , and angle PDC =15°, find :
a. Angle AQD
b. Angle APD
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Answer:
This is a simple question of triangle measurnment.
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Answer:
Angle AQD= 45
Angle APD= 55
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