Math, asked by rageenisravankumar20, 2 months ago

d3+d2+d+1 root of these equation​

Answers

Answered by ayush7526
1

Answer:

d3+d2+d+1=0

This deals with linear equations with one unknown.

Overview

Steps

Topics

3 solution(s) found

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Step by Step Solution

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Reformatting the input :

Changes made to your input should not affect the solution:

(1): "d2" was replaced by "d^2". 1 more similar replacement(s).

Step by step solution :

STEP

1

:

Checking for a perfect cube

1.1 d3+d2+d+1 is not a perfect cube

Trying to factor by pulling out :

1.2 Factoring: d3+d2+d+1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: d+1

Group 2: d3+d2

Pull out from each group separately :

Group 1: (d+1) • (1)

Group 2: (d+1) • (d2)

-------------------

Add up the two groups :

(d+1) • (d2+1)

Which is the desired factorization

Polynomial Roots Calculator :

1.3 Find roots (zeroes) of : F(d) = d2+1

Polynomial Roots Calculator is a set of methods aimed at finding values of d for which F(d)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers d which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 1 and the Trailing Constant is 1.

The factor(s) are:

of the Leading Coefficient : 1

of the Trailing Constant : 1

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 2.00

1 1 1.00 2.00

Polynomial Roots Calculator found no rational roots

Equation at the end of step

1

:

(d2 + 1) • (d + 1) = 0

STEP

2

:

Theory - Roots of a product

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

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