Question

David's company reimburses his expenses on food, lodging, and conveyance during business trips. The company pays $60 a day for food and lodging and $0.65 for each mile traveled. David drove 600 miles and was reimbursed $3,390. Part A: Create an equation that will determine the number of days on the trip. (3 points) Part B: Solve this equation justifying each step with an algebraic property of equality. (6 points) Part C: How many days did David spend on this trip?

Answer 1

Answer:

0.65*600+60x=3390 (This is the required equation)

50 days duration of trip.

Step-by-step explanation:

Part A:

Given that, during business trips, the company pays David $60 per day for food and lodging and $0.65 for each mile he traveled.

Let us assume that in this trip David drove 600 miles (given) and it was of x days duration.

If David was reimbursed $3390 for this trip.

Then, the equation can be written that

0.65*600+60x=3390..... (1)

This is the required equation to determine the number of days on the trip.

(Answer)

Part B:

From equation (1), we have

0.65*600+60x=3390

⇒390+60x=3390

⇒60x=3390-390

⇒60x=3000

⇒x= 50 days

So, this is the solution of equation (1).

(Answer)

Part C:

Therefore, David spent 50 days on this trip.

(Answer)