DE II OQ and DF II OR show that EF II QR
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Check this attachment :-)
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In triangle PQO,DE||OQ
PE/EQ=PD/DO-1 (by BPT)
in triangle POR,DF||OR
PF/FR=PD/DO-2 (by BPT)
from 1 and 2,
PE/EQ=PF/FR
Therefore,EF||QR.(by BPT)
PE/EQ=PD/DO-1 (by BPT)
in triangle POR,DF||OR
PF/FR=PD/DO-2 (by BPT)
from 1 and 2,
PE/EQ=PF/FR
Therefore,EF||QR.(by BPT)
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