Math, asked by MeGourav, 1 year ago

Dear friendz, please help me in simplifying it step by step.....

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Answers

Answered by Steph0303
2
Hey mate !!

Here's the answer !!

Refer to the attachment !!

Hope it helps !!

Cheers !!
Attachments:

MeGourav: Thanks
Steph0303: my pleasure mate (:-))
siddhartharao77: Sorry for disturbance. I think its wrong
siddhartharao77: Ok.Lemme tell u. (2n + 1)(2n - 1) = 4n^2 - 1. U have written 2n^2 - 1
Answered by siddhartharao77
1
 Given : \frac{ x^{2n+1} *  x^{(2n+1)(2n-1)}  }{ x^{n(4n-1)} *  (x^2){2n+3}  }

 \frac{ x^{2n + 1 + (2n + 1)(2n - 1)} }{ x^{4n^2 - n + 4n + 6} }

 \frac{ x^{2n + 1 + 4n^2 - 1} }{ x^{4n^2 + 3n + 6} }

 \frac{ x^{4n^2 + 2n} }{ x^{4n^2 + 3n + 6} }

 x^{4n^2 + 2n - 4n^2 - 3n - 6}

 x^{-n-6}


Hope this helps!

siddhartharao77: :-)
siddhartharao77: Any doubts. Ask me. Gud luck!
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