Question

Decide which of the following are equal sets and which are not ? Justify your answer.
A = { x|3x-1=2}
B = { x|x is a natural number but x is neither prime nor composite}
C = {x|x∈N,x<2}

Answer 1

$\textbf{Answer :}$

Given,

A = { x | 3x - 1 = 2 } = 1

B = { x | x is a Natural number but x is neither prime nor composite }

= 1

C = { x | x ∈ |N, x < 2 } = 1

So, we see that all the sets are equal.

#$\bold{MarkAsBrainliest}$

Answer 2

Answer:

all below sets are equal

A = { x|3x-1=2}

B = { x|x is a natural number but x is neither prime nor composite}

C = {x|x∈N,x<2}

Step-by-step explanation:

A = { x|3x-1=2}  

=> 3x - 1 = 2

=> 3x = 3

=> x = 1

A = {1}

B = { x|x is a natural number but x is neither prime nor composite}

x = Natural number = 1 ,2  ,3  ....

but 1 is the only number which is neither prime nor composite

B = {1}

C = {x|x∈N,x<2}

xx∈N so x = 1 , 2 , 3 ,...

but x < 2

so x = 1

C = {1}

A = {1} , B = {1} , C = {1}

=> A = B = C = {1}

all sets are equal