Question

def f(n): s=0 for i in range(1,n+1): if n%i == 0: s = s+1 return(s%2 == 1)

The function f(n) given above returns True for a positive number n if and only if:

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Answer 1

Answer:

looking for the same answer

Explanation:

Answer 2

"If the value of n will be a perfect square" is the correct answer for the above question.

Explanation:

• The above code is in python language which checks the value which is entered by the user at the time of calling function is a perfect square or not.
• The function defined "f" is used to check the number x is a perfect square or not, if the number is a perfect square, then it returns true otherwise it returns false.
• To check the perfect square, the above function firstly counts the number of a factor of number x. then it checks that the total factor is equal to the (multiple of 2) +1 or not. if it is, it prints true otherwise false.
• It is because if a number is a perfect square then its total factor is equal to the (multiple of 2)+1.

Learn More:

• Python program : https://brainly.in/question/5558161