Question

Define a Python function remdup(l) that takes a nonempty list of integers l and removes all duplicates in l, keeping only the
first occurrence of each number. For instance:

>>> remdup([3,1,3,5])
[3, 1, 5]

>>> remdup([7,3,-1,-5])
[7, 3, -1, -5]

>>> remdup([3,5,7,5,3,7,10])
[3, 5, 7, 10]
Write a Python function sumsquare(l) that takes a nonempty list of integers and returns a list [odd,even], where odd is the sum of squares all the odd numbers in l and even is the sum of squares of all the even numbers in l.

Here are some examples to show how your function should work.

>>> sumsquare([1,3,5])
[35, 0]

>>> sumsquare([2,4,6])
[0, 56]

>>> sumsquare([-1,-2,3,7])
[59, 4]
A two dimensional matrix can be represented in Python row-wise, as a list of lists: each inner list represents one row of the matrix. For instance, the matrix

1 2 3 4
5 6 7 8
would be represented as [[1, 2, 3, 4], [5, 6, 7, 8]].

The transpose of a matrix converts each row into a column. The transpose of the matrix above is:

1 5
2 6
3 7
4 8
which would be represented as [[1, 5], [2, 6], [3, 7], [4, 8]].

Write a Python function transpose(m) that takes as input a two dimensional matrix m and returns the transpose of m. The argument m should remain undisturbed by the function.

Here are some examples to show how your function should work. You may assume that the input to the function is always a non-empty matrix.

>>> transpose([[1,2,3],[4,5,6]])
[[1, 4], [2, 5], [3, 6]]

>>> transpose([[1],[2],[3]])
[[1, 2, 3]]

>>> transpose([[3]])
[[3]]

Answer 1

Answer:

def remdup(l):

 seen = set()

 for i in range(len(l)-1, -1, -1):

   if l[i] in seen:

       del l[i]

   else:

       seen.add(l[i])

 return(l)

Explanation: