degree of dissociation of 0.1 N CH3COOH is?
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Answered by
58
Degree of dissociation = (Ka/Concentration)^1/2
a= (10^-5/0.1)^1/2
a=0.01
(a=degree of dissociation.)
Its answer is 0.01 by substituting the values in the formula (ka/concentration)^1/2 which gives us degree of dissocaition
kvnmurty:
you should give the formula for Ka and find [ H+] in some steps.... otherwise it is not easy for the inquirer and users to understand....
@34545 pls give more details here in comments.
Answered by
38
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accually i have to put ur answer as the braneliest but by mistake....
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