Density of 2.03M aqueous solution of acetic acid is 1.017g/ml molecular mass of acetic acid is 60.calculate the molality of the solution.
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molality=M×1000/d×1000-M×Mmsolute
M=2.03
d=1.017
Mm=60
molality=2.03×1000/1.017×1000-2.03×60
=2.2molal
M=2.03
d=1.017
Mm=60
molality=2.03×1000/1.017×1000-2.03×60
=2.2molal
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