Question

derivation of the equation of the motion in class 9th physics​

Answer 1

NANBA..

Derivation of First Equation of Motion

Derivation of First Equation of MotionThe first equation of motion is:

Derivation of First Equation of MotionThe first equation of motion is:v = u + at

Derivation of First Equation of MotionThe first equation of motion is:v = u + atDerivation of First Equation of Motion by Algebraic Method

Derivation of First Equation of MotionThe first equation of motion is:v = u + atDerivation of First Equation of Motion by Algebraic MethodIt is known that the acceleration (a) of the body is defined as the rate of change of velocity.

Derivation of First Equation of MotionThe first equation of motion is:v = u + atDerivation of First Equation of Motion by Algebraic MethodIt is known that the acceleration (a) of the body is defined as the rate of change of velocity.So, the acceleration can be written as:

Derivation of First Equation of MotionThe first equation of motion is:v = u + atDerivation of First Equation of Motion by Algebraic MethodIt is known that the acceleration (a) of the body is defined as the rate of change of velocity.So, the acceleration can be written as:a = v − ut

Derivation of First Equation of MotionThe first equation of motion is:v = u + atDerivation of First Equation of Motion by Algebraic MethodIt is known that the acceleration (a) of the body is defined as the rate of change of velocity.So, the acceleration can be written as:a = v − utFrom this, rearranging the terms, the first equation of motion is obtained, which is:

Derivation of First Equation of MotionThe first equation of motion is:v = u + atDerivation of First Equation of Motion by Algebraic MethodIt is known that the acceleration (a) of the body is defined as the rate of change of velocity.So, the acceleration can be written as:a = v − utFrom this, rearranging the terms, the first equation of motion is obtained, which is:v = u + at..

HOPE USEFULL...

Answer 2

Answer:

Answer:

$\sf Hlo \: mate \: here's \: your \: answer \: Hope \: it \: helps!$

$\huge \sf Equations \: of \: Motion$

$\sf Consider \: a \: body \: moving \: with \: initial \: velocity \: 'u' \: changes \: it's \: velocity \: to$

$\sf 'v' \: after \: 't' \: seconds. \: Let \: 's' \: is \: the \: displacement \: and \: 'a' \: is \: the$

$\sf acceleration \: of \: the \: body.$

From the defenition of acceleration

a = Change in velocity / time

= (v- u )/ t

by cross multiplication

. at = v - u

$\sf \implies v = u + at$

2) displacement (s) = average velocity × time

S = (u + v /2) × t

= [u + (u + at )] / 2 ×t

=( 2u + at ) / 2. × t

= 2ut/2 + 1/2 × ${at}^{2}$

$\sf \implies S \: = \: ut \: + \: \frac{1} {2} {at}^{2}$

3). v = u + at

by squaring on both sides

$\sf {v}^{2} \: = \: ({u \: + \: at})^{2}$

= $\sf {u}^{2} \: + \: 2uat \: + \: {a}^{2} {t}^{2}$

$\sf \implies {v}^{2} \: = \: {u}^{2} \: + \: 2as$

Hope it helps you.....