Question

derivative of sincubex power 2/3​

Answer 1

Step-by-step explanation:

Hello dear my self RAVI Gupta from Ayodhya Uttar Pradesh

$= \frac{d \ }{dx} ( { \sin(x)})^{ \frac{2}{3} }$

$= \frac{2}{3}.( \sin(x) )^{ \frac{ - 1}{3} } . \frac{d}{dx} . \sin(x)$

$= \frac{2}{3}.( \sin(x) ) ^{ \frac{ - 1}{3} } . \cos(x)$

$= \frac{2}{3}. \frac{ \cos(x) }{ \sqrt[3]{ \sin(x) } }$