derive a quadratic polynomial for which the sum of zeroes=1/3 and the product of zeroes=1/2
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Answered by
0
hey!!!!
As we know for this quadratic formula
eqn will always be
k(x^2-sum of zeroes x +product )
so,
k(x^2-1/3x+1/2)
by taking lcm
k(6x^2 -2x+3)
k=1/3
the quadratic polynomial will be
6x^2 -2x+3
plz mark it as brainiest
As we know for this quadratic formula
eqn will always be
k(x^2-sum of zeroes x +product )
so,
k(x^2-1/3x+1/2)
by taking lcm
k(6x^2 -2x+3)
k=1/3
the quadratic polynomial will be
6x^2 -2x+3
plz mark it as brainiest
Answered by
1
ANSWER :
Let alpha+beta be 1/3 and alpha*beta be 1/2
quadratic equation= x^2-(alpha+beta)x+(alpha*beta)=0
substituting the values of alpha+beta and alpha*beta, we get
x^2-1/3x+1/2=0, taking the LCM of 3 and 2 as 6 we get,
6x^2-2x+3=0
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