Question

Derive an equation for the path of a projectile fired parallel to horizontal.

CLASS - XI PHYSICS (Kinematics)

Answer 1

let the initial velocity be u m/s.  angle of projection = 0

initial component of velocity in vertical direction = 0

horizontal displacement from initial position at t= 0sec,   = x = u t 
vertical displacement from initial position at t = 0 0sec,   =  y = -1/2 g t²

so t = x/u

Hence        y = - 1/2 g (x/u)² = - (g/2u²)  x²