Physics, asked by deep127, 1 year ago

derive an expression for distance covered by the particle in time equation s=ut+1/2at2

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Answered by 111mohan1111
1
considère a body having initial veolcity u accélération à time t, final velocity v distance s. average velocity =v+u/2. distance =average xtime s=v+u/2X t. v=u+at. s=u+at+u/2X t s=2u/2+at/2. = s=ut+1/2atsquare. hope it is use ful if u like it Mark It branellist answer
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