Question

Derive an expression for maximum height reached by the stone

Answer 1

if you Are asking maximum height during projectile motion then

it will be given by

Answer 2

Expression for maximum height reached by the stone $H = \frac{(u^{2}sin^{2}∅ )}{2g}$

Explanation:

Let H be the maximum height reached by the projectile in time t1

For vertical motion,

The initial velocity = usinθ

The final velocity =0

Acceleration =−g

Using

$v^{2} = u^{2} + 2as$

$0 = u^{2} sin^{2}∅ - 2gH$

$2gH = u^{2} sin^{2}∅$

$H = \frac{(u^{2}sin^{2}∅ )}{2g}$