Math, asked by nupurrane, 11 months ago

if l,m,n are real,l is not equal to m then the roots of the equation (l-m)x²-5(l+m)x-2(l-m)=0 are

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Answered by brunoconti

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if l,m,n are real,l is not equal to m then the roots of the equation (l-m)x²-5(l+m)x-2(l-m)=0 are​

Answers

if l,m,n are real,l is not equal to m then the roots of the equation (l-m)x²-5(l+m)x-2(l-m)=0 are