Question

Derive an expression for rise of

liquid in a capillary tube (Ascent formula)​

Answer 1

Answer:

Since liquid is wet, therefore, the meniscus is concave. Let 'r' be the radius of capillary tube, 'R' be the radius of meniscus and 'θ' the angle of contact. In figure (i), ... Now, inorder to attain the equilibrium, the liquid will rise in tube.

Explanation:

pls mark me as brainliest if it helps you and thank me

Answer 2

Explanation:

Lets say capillary of radius r is placed in a beaker containing a liquid of density & and water rises in the capillary the height h,

$P_B - P_C$ = $\frac{2T}{R}$                  -------(1)  

$P_c$ + ρgh = P$_A$                -------(2)

P$_B = P_O$                         ------(3)

$P_A = P_o$                          -------(4)

From (1),(2)&(3),(4)

$P_o - \frac{2T}{R}$ =  P ρgh

$\frac{2T}{R}$ = ρgh

h = $\frac{2T}{R\rho g}$

​h = $\frac{2T cos\theta}{\rho rg}$

​