Question

Derive an expression for the depth of centre of pressure from free surface of liquid of an

inclined plane surface submerged in the liquid.​

Answer 1

Answer:

Inclined plane

Step-by-step explanation:

inclined plane surface submerged in the liquid.

Answer 2

According to Law of Pascal, the strength of pressure at a spot in a static fluid is equal in all directions.

Explanation:

According to Pascal's Law, the pressure or strength of pressure at a place in a static fluid is equal in all directions. For a planar surface of any shape submerged in a liquid such that the plane of the surface produces an angle with the liquid's free surface:

A = Total area of an inclined surface  

h = Depth of the inclined area's centre of gravity from the free surface

h* = Distance of the liquid's centre of pressure from the free surface

                                                   $h*= \frac{I_{G} sin^{2}B }{Ah}$

                                                     $h*= \frac{I_{G} }{Ah}$

Surfaces with a vertical plane: B(angle)=90°

From the above equations, the following facts may be deduced:

• Because the factor $\frac{I_{G} }{Ah}$ is always positive for any plane surface, the centre of pressure is below the centroid.

• The closer the centre of pressure is to the centroid of the region, the deeper the surface is immersed in the liquid (i.e., the bigger the value of h). Because the depth of the centre of pressure is independent of the liquid's specific weight, it is the same for all liquids.

• Total Pressure: The total pressure on a liquid-immersed surface is proportional to its inclination to the liquid's surface.