Physics, asked by Pranaswi1304, 1 year ago

Derive an expression for the intensity at any point on the observation screen in youngs double slit experiment

Answers

Answered by abhi178
25

we know, intensity of wave depends on amplitude of wave. e.g., intensity of wave is directly proportional to square of amplitude of wave.

mathematically, I = KA², where K is proportionality constant, I is intensity and A is amplitude.

if two waves, y_1=A_1sin\omega t

and y_2=A_2sin(\omega t+\delta)

resultant amplitute, A=\sqrt{A_1^2+A_2^2+2A_1A_2cos\delta}

so, A^2=A_1^2+A_2^2+2A_1A_2cos\delta

or, \boxed{\bf{I=I_1+I_2+2\sqrt{I_1I_2}cos\delta}}

this is the expression for the intensity at any point on the observation screen in Young's Double slit experiment.

Similar questions