Question

Derive an expression for the potential energy of an elastic stretched spring
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Answer 1

Answer:

Derive an expression for elastic potential energy in a stretched wire. Hooke's Law, F = -kx, where F is the force and x is the elongation. The energy stored can be found from integrating by substituting for force.The energy stored = kx2/2, where x is the final elongation.

Explanation:

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Answer 2

Answer:

potential energy is denoted by Ep