derive the equation of motion v=u+at using graphical method.
a train starting from rest attains a velocity of 72 km per hour in 5 minutes assuming the acceleration is uniform find the acceleration and the distance travelled by the train for attaining this velocity
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Answered by
62
t=5 mins
U=0
v=72kmh¹
72×5/18
=20ms¹
a)a=v-u/t
20-30/300
1/15ms²
b)s= ut +1/2at²
0×300+1/2×1/15×300²
0+1/30×90000
=3000m
3km
U=0
v=72kmh¹
72×5/18
=20ms¹
a)a=v-u/t
20-30/300
1/15ms²
b)s= ut +1/2at²
0×300+1/2×1/15×300²
0+1/30×90000
=3000m
3km
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24
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