Question

derive the expression for the mutual inductance of two long solenoids​

Answer 1

Answer:

Number of turns per unit length in order (primary) solenoid, n = N1/l If I1 is the current flowing in primary solenoid, the magnetic field produced within this solenoid. The flux linked with each turn of inner solenoid coil is Φ2 = B1A2, where A2 is the cross-sectional area ofinner solenoid

Explanation:

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Answer 2

Answer:

Number of turns per unit length in order (primary) solenoid, n = N1/l If I1 is the current flowing in primary solenoid, the magnetic field produced within this solenoid. The flux linked with each turn of inner solenoid coil is Φ2 = B1A2, where A2 is the cross-sectional area ofinner solenoid.