Question

Derive the expression for the pressure at a point due to a liquid​

Answer 1

Answer:

height *density *gravity

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Answer 2

Answer:

consider a static liquid of density ρ in a cylinderical jar to a height h. let A be the area 9f cross section of cylinder jar

The net downward force on the base=weight of the liquid.

F=mass of the liquid×g

F=volume×density×g

F=area of cross section×height×density×g

F=Ahρg

$pressure \: P \: =\frac{F}{A}=\frac{Ahρg}{A}$

∴P=ρgh