Question

For what value of 't' the expression (2x²-5x+10) and (2x²-tx+2t) are equal–
options are–
(I) 2
(ii)5
(iii)3
(iv)4
Who ever will answer my questions I will mark him as a brainly. So quick answer and with explanation steps by steps​

Answer 1

2x2-5x+10=2x2-tx+2t

2x2 cancels from both sides, now we have

-5x+10=-tx+2t

5(2-x)=t(2-x)

2-x term cancels on both sides

t=5

So second option is correct

Answer 2

The value of t = 5

Given :

The expression (2x² - 5x + 10) and (2x² - tx + 2t) are equal

To find :

The value of 't' for which expression (2x² - 5x + 10) and (2x² - tx + 2t) are equal

(i) 2

(ii)5

(iii)3

(iv)4

Solution :

Step 1 of 2 :

Write down the given expressions

Here the given expressions are (2x² - 5x + 10) and (2x² - tx + 2t)

Step 2 of 2 :

Find the value of t

Since expression (2x² - 5x + 10) and (2x² - tx + 2t) are equal

∴ (2x² - 5x + 10) = (2x² - tx + 2t)

⇒ - 5x + 10 = - tx + 2t

Equating coefficient of x and constant term in both sides we get

- 5 = - t and 10 = 2t

Now , - 5 = - t gives t = 5

Again , 10 = 2t gives t = 5

So the required value of t = 5

Hence the correct option is (ii) 5

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