Question

derive the second equation of motion S = ut+1/2at^2 numerically

Answer 1

hey here is your answer,

we know that second equation of motion s =ut+1/2at^2
consider a body moving with a velocity 'u' after 't' seconds final velocity became 'v'.
Therefore , initial velocity ='u'
and final velocity ='v'.
Let 's' be the distance travelled by a body, 'a' is the acceleration.
We know that average velocity = u+v/2.
distance travelled(s)= average velocity/2 ×time=u+v/2×t.
we know that first equation of motion is v= u+at.
Putting the value of v in equation 1,
s=(u+u+at/2)t = (2u+at/2)t
=(2u/2+at/2)t
=(u+at/2)t
=(ut+at/2)t
=ut+at^2/2
s=ut+1/2at^2.
Hence, equation derived.