Question

Derive v2=vo2+2ax using v-t graph

Answer 1

Answer:

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Answer 2

Answer:

To derive this, you need to eliminate time from the given equations. Start with

vf = vi + at ⇒ t = (vf - vi)/a

Plug this expression for t into

d = vit + at2/2

and get

d = vi(vf - vi)/a + a[(vf - vi)/a]2/2

Multiply both sides by 2a and get

2ad = 2vivf - 2vi2 + (vf2 - 2vivf + vi2)]

2ad = vf2 - vi2

vf2 = vi2 + 2ad

Explanation:

Kashuuu~