Question

describe the motion of a body which is accelerating at a constant rate of ten meter per second squared if the body starts from rest how much distance will it cover in two seconds

Answer 1

Answer:

the traversed distance will be 20 m

Explanation:

From the equations of motion we know

    v=u+at

    s=ut+(1/2)at^2

    v^2=u^2+2as

    a=(v-u)/t

in your question the given values are

    acceleration,a=10 m/s^2

    intial velocity,u=0 m/s

    time,t = 2 s

the only formula including all these and the distance traversed i the 2nd one

so traversed distance, s=0*t+(1/2)*10*2^2

                                         =0+1/2 *40

                                         =20 m

Hope this helps

Answer 2

Explanation:

20 Ms is the answer okomomoko