Question

determinant prove that =(a+b+c)³

Answer 1

=(a+b+c)(a+b+c)(a+b+c)
=(a²+ab+ac+ba+b²+bc+ca+cb+c²)
(a+b+c)
=(a²+b²+c²+2ab+2bc+2ca)(a+b+c)
=(a³+ab²+ac²+2a²b+2abc+2ca²+a²b
+b³+bc²+2ab²+2b²c+2abc+a²c+b²c
+c³+2abc+2bc²+2c²a)
=then add all terms give
=a³+b³+c³+3(b+c)(c+a)(a+b)
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