Determine if x^4+x^3+x^2+x+1 has(x+1) a factor
Answers
Answered by
0
Explanation:
p(x) = x^4 + x³ + x² + x + 1
g(x) = x + 1
x + 1 = 0
x = -1
put x in p(x&
p(-1) = (-1)^4 + (-1)³ + (-1)² + (-1) + 1
= 1 + (-1) + 1 - 1 + 1
= 1 - 1 + 1 - 1 + 1
= 3 - 2
= 1
p(-1) ≠ 0
so x + 1 is not a factor of p(x)
Similar questions