Determine k so that (3k-2),(4k-6)and(k+2) are three consecutive terms of AP
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If (3k-2), (4k-6), (k+2) are three consecutive term of an A.0 then;
Arithmetic Mean :
= (4k-6) = {(3k-2) + (k+2)} ÷ 2
(4k -6)×2 = 3k -2+k+2
8k-12 = 4k
4k = 12
k = 3
hope this helped,
plzzz mark as brainliest.......
Arithmetic Mean :
= (4k-6) = {(3k-2) + (k+2)} ÷ 2
(4k -6)×2 = 3k -2+k+2
8k-12 = 4k
4k = 12
k = 3
hope this helped,
plzzz mark as brainliest.......
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