Question

determine the A.P whose third term is 16 and 7 th term exceeds the 5 th term by 12

Answer 1

Hey user !!

Here is your answer !!

⭐______________________________________________⭐

Given ->

a3=a+2d=16

a5=a+4d

a7=a+6d

Solution ->A. T. Q

a+6d-a-4d=12

2d=12

d=12/2

d=6

Subsituting value of d

a+2d=16

a + 2(6) =16

a + 12 = 16

a = 16 -12

a= 4

Hence the AP is 4, 10 ,16 ,22

Hope it is satisfactory :-)

⭐____________________________________________⭐