Determine the AP whose fourth term is 18 and the difference of the ninth term from the
fifteenth term is 30.
Answers
Answered by
2
Answer:
AP is : 3,8,13,18,23... so on
Step-by-step explanation:
a+3d=18
a+14d - (a+8d) = 30; 6d=30
d=5;
a + 3*(5) = 18;
a=3;
AP is : 3,8,13,18,23... so on
Answered by
3
Answer:
it is given that 4th term is 18
a4= 18
a + 3d = 18
a = 18 - 3d
Also, a15 - a9 = a+ 14d - 1 - 8d = 30
6d = 30
d = 5
thus , from (1),we get ,
9 = 18 - 15 = 3
Therefore the AP is:
3,8,13,18,23...........
Step-by-step explanation:
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