determine the initial velocity and acceleration of a particle travelling with uniform acceleration in a straight line if it travels 55m in the 8 th second and 85 m in the 13th second
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Distance traveled by a particle in nth second is given by
Sn = u + (n-1/2) a
55 = u + (8 - 1/2) a
u + 15a /2 = 55 --- equation 1
u + 25a/2 = 85 --- equation 2
subtract eq 1 from eq 2
10a/2 = 30 a = 6 m /sec²
u + 15*6/2 = 55 u = 55-45 = 10 m/sec
Sn = u + (n-1/2) a
55 = u + (8 - 1/2) a
u + 15a /2 = 55 --- equation 1
u + 25a/2 = 85 --- equation 2
subtract eq 1 from eq 2
10a/2 = 30 a = 6 m /sec²
u + 15*6/2 = 55 u = 55-45 = 10 m/sec
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