Math, asked by Nishthaakukreja5240, 8 months ago

Determine the lowest natural number which when divided by 16, 28, 40, 77 leaves remainder 8 in each case.

Answers

Answered by ls6436736
6

Answer:

First we will take the LCM of 16,28,40,77

LCM=6160

As we have to take out the lowest natural number , so

have to take out the lowest natural number , so ; Required number = 8

have to take out the lowest natural number , so ; Required number = 8Lowest natural number = 6160+8

have to take out the lowest natural number , so ; Required number = 8Lowest natural number = 6160+8 =6168

Answered by harshinipriyakarthi
0

Answer:

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Step-by-step explanation:

ans 6160+8

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