Question

Determine the molarity of given KMnO solution by titrating it against M/20
Oxalic acid
solution.​

Answer 1

Molarity and strength determination of the $KMnO4$ solution This chemical reaction is a redox reaction

Explanation:

• AIM :- Determination of the strength of potassium permanganate with the help of  oxalic acid
• Solutions required :- $M/20$ Oxalic Acid, Potassium Permanganate,
• Reaction against the chemical analysis of oxalic acid
• The titrant is in the chemical analysis and the oxalic acid is the analyte.
• The reaction between potassium permanganate and oxalic acid occurs in an acidic medium and acidity is produced by dilute. Here the pointer itself works.
• Take 10 ml solution of oxalic acid in a flask.
• Add 5ml 1.0M sulfuric acid to it. First heat the solution to 50-60 ℃ with a solution of potassium permanganate.
• Initially pink color of potassium permanganate reacts with oxalic acid
• The process in which a chemical change takes place is called a chemical reaction.
• Titrate till permanent pink colour is obtained.
• Calculation of molarity is determined with the help of $M1V1=M2V2$