determine the natural of the root of the quadratic equation 2x²-3x-4=0
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Step-by-step explanation:
The given quadratic equation is ;
2x² + 3x - 4 = 0 .
Comparing with the general form of the quadratic equation ax² + bx + c = 0 , we have ;
a = 2 , b = 3 , c = -4
Now,
The discriminant of the given quadratic equation will be given as ;
=> D = b² - 4ac
=> D = 3² - 4×2×(-4)
=> D = 9 + 32
=> D = 41
=> D > 0
Clearly,
The discriminant of the given quadratic equation is greater than zero .
Thus,
Its roots will be real and distinct .
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