Question

determine the natural of the roots of the equation X2 - 2x + 9 upon 4 = 20​

Answer 1

Answer:

X²-2x+9upon 9=20

....multiplying both side by 4

4X²-8x+9=80

4X²-8x+9-80=0

4X²-8x-71=0

comparing with ax²+bx+c=0

we get ,

a=4. b=8. c=-71

∆=b²-4ac

=8²-4×4×-71

=64-16-71

=48-71

=-23

∆=-23

As ∆is smaller than zero,the root of the quadratic equation are not real