determine the nature of roots for the quadratic equation root 2x²+2 root2x- 2 root 3 =0
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Answer:
√6 , -(√6/3 ) are two roots of given Quadratic equation.
Step-by-step explanation:
Explanation:
Given quadratic equation:
√3x²-2√2x-2√3=0
Splitting the middle term, we get
=> √3x²-3√2x+√2x-2√3=0
=> √3x²-√3×√3×√2x+√2x-√2×√2×√3=0
=> √3x(x-√6)x+√2(x-√6)=0
=> (x-√6)(√3x+√2)=0
=> x-√6=0 Or √3x+√2=0
=> x = √6 Or x = (-√2)/√3
=> x= √6 Or x = -(√6)/3
Therefore,
√6 , -(√6/3 ) are two roots of given Quadratic equation.
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