Question

determine the nature of roots for the quadratic equation root 2x²+2 root2x- 2 root 3 =0​

Answer 1

Answer:

√6 , -(√6/3 ) are two roots of given Quadratic equation.

Step-by-step explanation:

Explanation:

Given quadratic equation:

√3x²-2√2x-2√3=0

Splitting the middle term, we get

=> √3x²-3√2x+√2x-2√3=0

=> √3x²-√3×√3×√2x+√2x-√2×√2×√3=0

=> √3x(x-√6)x+√2(x-√6)=0

=> (x-√6)(√3x+√2)=0

=> x-√6=0 Or √3x+√2=0

=> x = √6 Or x = (-√2)/√3

=> x= √6 Or x = -(√6)/3

Therefore,

√6 , -(√6/3 ) are two roots of given Quadratic equation.