Determine the nature of the roots of quadratic equation 3x²+2x-9= 0
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Answer:
unequal roots
Step-by-step explanation:
Given Quadratic equation is
3x²+2x-9=0
discriminant D= b^2 -4ac
= 2^2- 4(3)(-9)
= 4 + 144
= 148
148 greater than 0
b^2-4ac is greater than 0
so it have unequal roots
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