Question

Determine the number of Bromide ion in 0.2 mole of mgbr2.​

Answer 1

Solution:

Solution:Mass of 1 mole of magnesium bromide (MgBr2) = 24 + 2 × 80 = 24 + 160 = 184 gSo 184 g MgBr2 = 1 moleBut 1 molecule of MgBr2 contains 2 bromide ions.Br- ions present= 2 × 6 × 1023 bromide ions.If 1 mole of MgBr2 contains = 12 × 1023 bromide ions.0.2 mole of MgBr2 contains = 2.4 × 1023 bromide ions.

Answer 2

Masss of 1 mole of MgBr2= 1(Mg) + 2(Br)

=>   1(24) + 2(80)      =>       24 + 160

=   184g

184g MgBr2 = 1 mole

1 molecule of MgBr2 contains 2 Bromide ions

Br ions present = 2×6.022×10²³ bromide ions

=>    12.022×10²³    = 1.2022×10²⁴

1 mole of MgBr2 contains = 1.2022×10²⁴ bromide ions

0.2 mole of MgBr2 contains = 0.2×1.2022×10²⁴ bromide ions

=>   2.4044×10²³

Hope this is helpfull!!