Question

Determine the number of bromide ion in 8mole of HgBr2(in terms of $N_{A}$)

Answer 1

Answer:

Mercury [II] bromide in ionic form

HgBr₂ →Hg⁺ + 2Br⁻

1 molecule of HgBr₂ contain 2Br⁻

Hence, 1 mole of HgBr2 contain 2Br-

Therefore,

8 mole of HgBr₂ contain = 2 x 8 = 16Br-

= 16 x 6.023 x 10²³ = 9.636 x 10²⁴ ions

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Answer 2

Answer:

x²∈Z+,(4x²)=

(i)4*0²=0, but y²≠12

(ii)4*1²=4, but y²≠8

(iii)4*2²=16>12

(a)when y=0,1,2,3→y²=0,1,4,9,

but 4x²≠12,11,8,3